Re: is $* the complete path?

[Assar Westerlund]

Alexandre Oliva <address@hidden> writes:
> Basename is far simpler:
> 
> % echo "$pathname" | sed 's,.*/,,'

So is this ok?

/assar

Index: man/Makefile.am
===================================================================
RCS file: /cvs/autoconf/man/Makefile.am,v
retrieving revision 1.3
diff -u -w -u -w -r1.3 Makefile.am
--- man/Makefile.am     2000/12/15 08:25:10     1.3
+++ man/Makefile.am     2000/12/15 09:56:32
@@ -24,12 +24,13 @@
 SUFFIXES = .x .1
 
 .x.1:
-       test -f $(top_builddir)/$* && prog=$(top_builddir)/$*; \
-       test -f $(top_srcdir)/$* && prog=$(top_srcdir)/$*; \
+       f=`echo "$*" | sed 's,.*/,,'`; \
+       test -f $(top_builddir)/$$f && prog=$(top_builddir)/$$f; \
+       test -f $(top_srcdir)/$$f && prog=$(top_srcdir)/$$f; \
        if test -n "$$prog"; then \
          echo "Updating man page $@"; \
          $(HELP2MAN) \
-           --include=$(srcdir)/$*.x \
+           --include=$(srcdir)/$$f.x \
            --include=$(srcdir)/common.x \
            --output=$@ $$prog; \
        else \