help with AC_ARG_WITH logic

[Ayodele(jimmy) Onibokun]

Hi --
 i'm having some problem with the logic in this ac_arg_with macro:
AC_ARG_WITH([gfortran],
AC_HELP_STRING([--with-gfortran], [use GNU gfortran]),
[if test $withval = yes; then ----- I'm not sure if I actually need the 
semicolon in this line and also the '[' that preceeds the "if" statement.
F77=gfortran -----------
else |
F77=$withval |
fi | I think something is not done right here...I'm not exactly sure what is 
wrong here but can anyone help pls.
fortran_gfortran=1])--|

Thanks alot,
Ayodele.
-- 
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- Thank you and have a good day.
Ayodele.
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