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how to detect int64?


From: Jay K
Subject: how to detect int64?
Date: Mon, 19 Jul 2010 02:01:15 +0000

scary configure output noticed:

checking for int64_t... int
checking for uint64_t... unsigned int

config.h:
/* Define to the type of a signed integer type of width exactly 64 bits if
   such a type exists and the standard includes do not define it. */
#define int64_t int

Looks like a known/fixed regression in autoconf 2.64.

bash-3.2$ gcc -v
Using built-in specs.
Target: alpha-dec-osf4.0g
Configured with: /usr/users/m3build/src/gcc-4.2.4/configure 
-prefix=/usr/users/m3build -disable-bootstrap
Thread model: posix
gcc version 4.2.4


http://www.mail-archive.com/address@hidden/msg02512.html


So, question is, what is wrong with the following seems-simple algorithms:


1) Find the types that exist, char, short, int, long, long long,
  their sizes, #include <limits.h>, multiply by CHAR_BIT?
  Or probably assume all but long long exist.
  Or error out if anything other than long long doesn't exist
  (or __int64 instead)

Or:

2) #include <limits.h>, compare UNSIGNED_FOO_MAX for equality to 255, 65535, 
4GB, etc.?
 Before attempting to check for equal with the maximum 64bit number, since
 preprocessor might reject such a large number you would:
 See if long long exists, if so, ok.
 See if unsigned long max > 4GB. If so, proceed to compare for equality with ..
 You also have to hunt around slightly for the name of "ULONGLONG_MAX". Granted.


Don't want to depend on limits.h?


Honestly, what I often do is just:


typedef signed char INT8;
typedef short INT16;
typedef int INT32;
#if defined(_MSC_VER) || defined(__DECC)
typedef __int64 INT64;
#else
typedef long long INT64;
#endif


But I understand the problems with that.
None of those typedefs are *guaranteed* to be correct.


Thanks,
 - Jay                                    


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