Can't source itself?

[Peter Backlund]

Hi, 

I posted the "Possible source bug?" a few weeks ago, but no one responded. 
Is it expected behaviour to segfault when a script tries to source itself 
in? As in this script, named foo.sh:

#!/bin/bash
. ./foo.sh 

This will segfault upon execution. Infinite recursion should be more 
reasonable, or preferably that it recognices itself and returns an error 
message.