Re: "IFS=: for foo in $FOO:bar:baz; do" doesn't work properly

[Sven Mascheck]

Jonathan Kamens <jik@kamens.brookline.ma.us> wrote:

>         FOO="foo:bar:baz"
>         IFS=:
>         for ac_dir in $FOO:screlt:freeble; do
>             echo $ac_dir
>         done

But IFS is applied to separate _results_ of parameter expansion and
command substitution (and for the read builtin).