[50 character or so descriptive subject here (for reference)]

[Jim Thomas]

Configuration Information [Automatically generated, do not change]:
Machine: hppa1.1
OS: hpux10.20
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='hppa1.1' 
-DCONF_OSTYPE='hpux10.20' -DCONF_MACHTYPE='hppa1.1-hp-hpux10.20' 
-DCONF_VENDOR='hp' -DSHELL -DHAVE_CONFIG_H -DHPUX   -I.  -I. -I./include 
-I./lib -I/usr/local/include -g -O2
uname output: HP-UX atlas B.10.20 A 9000/712 2007201070 two-user license
Machine Type: hppa1.1-hp-hpux10.20

Bash Version: 2.05
Patch Level: 0
Release Status: release

Description:
        Continuing with trying to hide the differences between HP's "POSIX"
shell and bash, using the previous suggestion, my function still fails.  It
appears that the variable I declare in the function is not made global.
The equivalent "set -A $ArrayName $*" in HP's shell does return a value for
pwdArray whether it is executed directly or is stuffed in Command and eval'ed
as with the function below.  I read the FUNCTIONS section of bash.1 to
indicate that my declare should not be local.

Repeat-By:

With the following in bash.bash :
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
SetArray () {
        local ArrayName Command
echo sa start =$*=
        ArrayName=$1
        shift
echo sa name =$ArrayName=
echo sa rest =$*=
        Command="declare -a $ArrayName=($*)"
echo sa com =$Command=
        eval "$Command"
echo sa array =${pwdArray[*]}=
}

typeset pwdArray
SetArray pwdArray h thomas
echo after array =${pwdArray[*]}=
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<

atlas ~ > /usr/local/src/gnu/bash-2.05/bash
bash-2.05$ . bash.bash
sa start =pwdArray h thomas=
sa name =pwdArray=
sa rest =h thomas=
sa com =declare -a pwdArray=(h thomas)=
sa array =h thomas=
bash-2.05$ . bash.bash
sa start =pwdArray h thomas=
sa name =pwdArray=
sa rest =h thomas=
sa com =declare -a pwdArray=(h thomas)=
sa array =h thomas=
after array ==
bash-2.05$