Re: how to make an alphabetical counter

[David D]

In fact I d like to make a bash script that create a dir for each of
alphabetcal char something like :

# 1-> a ... 26->z

# from 97 lower case -> 122

# from 65 upper case -> 90

#number=1

#eval "echo \$'\\$(printf %o "$[$number+65]")'"

#number=$number+1

#eval "echo \$'\\$(printf %o "$[$number+96]")'"

# créer les 26 rep avec les lettres de l'alphabet

number=97

while [ $number -le 122 ]

do

eval "mkdir \$'\\$(printf %o "$[$number]")'"

number=$number+1

done



but there is an error during the execution in the line :

number=$number+1

integer expression expected, how can i do to correct this.



mc.





> "David D" <dd@asi.fr> wrote:
> > Yes, I d like to make an alphabetical counter wich when I make ++ goes
from
> > a to b etc ...
>
> Use a numeric counter, and then to get the alphabetic character from
> the number, use:
> $ eval "echo \$'\\$(printf %o "$[$number+96]")'"
>
>
> paul