Re: how to make an alphabetical counter

[David D]

My objectif is to order some file (my mp3), into some directories, the
criteria is the first letter of the file, wich mean the first letter of the
artist name.

I make that script, nothing echo nothing moved, I surely forget something.

# 1-> a ... 26->z

# from 97 lower case -> 122

# from 65 upper case -> 90

declare -i number=97

while [ $number -le 122 ]

do

#echo "find -type d -name \"\$'\\$(printf %o "$[$number]")'*\" -exec mv -f
{} ./\$'\\$(printf %o "$[$number]")' \; "

#eval "find -type f -name \"^\$'\\$(printf %o "$[$number]")'*\" -exec echo
{} \; "

eval "find -type f -name \"^\$'\\$(printf %o "$[$number]")'*\" -exec mv -f
{} ./\$'\\$(printf %o "$[$number]")' \; "

number=$number+1

done



thanks.

> In fact I d like to make a bash script that create a dir for each of
> alphabetcal char something like :
>
> # 1-> a ... 26->z
>
> # from 97 lower case -> 122
>
> # from 65 upper case -> 90
>
> #number=1
>
> #eval "echo \$'\\$(printf %o "$[$number+65]")'"
>
> #number=$number+1
>
> #eval "echo \$'\\$(printf %o "$[$number+96]")'"
>
> # créer les 26 rep avec les lettres de l'alphabet
>
> number=97
>
> while [ $number -le 122 ]
>
> do
>
> eval "mkdir \$'\\$(printf %o "$[$number]")'"
>
> number=$number+1
>
> done
>
>
>
> but there is an error during the execution in the line :
>
> number=$number+1
>
> integer expression expected, how can i do to correct this.
>
>
>
> mc.
>
>
>
>
>
> > "David D" <dd@asi.fr> wrote:
> > > Yes, I d like to make an alphabetical counter wich when I make ++ goes
> from
> > > a to b etc ...
> >
> > Use a numeric counter, and then to get the alphabetic character from
> > the number, use:
> > $ eval "echo \$'\\$(printf %o "$[$number+96]")'"
> >
> >
> > paul
>
>