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Bash 2.05a isn't calling gawk as expected

From: nparks
Subject: Bash 2.05a isn't calling gawk as expected
Date: Wed, 5 Jun 2002 17:23:03 -0400

Configuration Information [Automatically generated, do not change]:
Machine: i686
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i686' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu' 
-I./lib -O2 -march=i386 -mcpu=i686
uname output: Linux acsvan0 2.4.18-4custom #3 Fri May 31 14:54:10 EDT 2002 i686 
Machine Type: i686-pc-linux-gnu

Bash Version: 2.05a
Patch Level: 0
Release Status: release

  A shell script which worked perfectly using "1.14.7(1)" fails to execute
properly using "2.05a.0(1)-release".  The purpose of the script is to parse
a session log file found in each user's home directory, and determine
whether a record belonging to some other user appears with today's date in
the file.
  The parsing is done by gawk, using variables passed to it by repeated use
of the "-v" parameter.
  I have tried this with both gawk 3.0.6 and gawk 3.1.1, and I get the same
results with either gawk.  When I use bash 1.14, bash calls gawk correctly
and gives it the proper parameters.  When I use bash 2.05a, each invocation
of gawk produces an error msg saying that gawk cannot open a file named

  Create files named "session_log" in the home directories of some users,
and run the script.

The shell script follows:

.....cut here.....



[ -s $blockflag ] && exit

for i in /home/*
  [ -d $i ] || continue
  cd $i

  [ -f session_log ] || continue

  tail session_log |
    gawk -v Username=`basename $i` -v TodayDate=`date '+%b %e'` \
      -v CurrentYear=`date '+%Y'` -v BlockFlag=$blockflag \
      '$0 ~ /[Uu]ser/ && $0 !~ Username && $0 ~ TodayDate \
      && $0 ~ CurrentYear \
      {print Username, $0 >> BlockFlag}'  


[ -s $blockflag ] || exit 0

cat $blockflag
cp -f $blockflag $pageflag

.....cut here.....

Beachwood, Ohio

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