Re: Using variables in variables names

[Dirk H. Schulz]

Paul Jarc schrieb:

> "Dirk H. Schulz" <dirk.schulz@kinzesberg.de> wrote:
>  
>
> > > ac=12  dings$ac=wasannersder
> > > -bash: dings12=wasannersder: command not found
> > >      
>
> Variable names in assignments are not subject to expansion.  So since
> "dings$ac", as-is, does not fit the syntax for variable names, it
> isn't treated as an assignment.  This will work:
> ac=12 eval "dings$ac=wasannersder"
>  
And how do I reference it then?

> ac=12
> eval "dings$ac=wasannersder"
> echo $dings12                                
> wasannersder                                          # that works
> echo $('$dings'$ac)                                 # trying to 
> substitute $ac before $dings...
> -bash: $dings12: command not found

Is there any way to reference it without anticipating the result of 
indirect referencing?

Dirk