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Re: exit status when setting local variables

From: Chet Ramey
Subject: Re: exit status when setting local variables
Date: Mon, 27 Mar 2006 14:50:20 -0500
User-agent: Thunderbird 1.5 (Macintosh/20051201)

Mike Frysinger wrote:
> not sure if this is a bug or feature ... take this little snippet:
> testit() {
>       local foo=$(false) ; echo $?
>       foo=$(false) ; echo $?
> }
> when we run the code, the output is:
> 0
> 1
> rather than intuitive:
> 1
> 1

It's intentional.

`local' returns success if the variable is correctly assigned a value
(for instance, the variable is not read-only).  The assignment statement
returns failure because that's how POSIX says assignment statements
behave.  (export and readonly behave the same way as local.)


``The lyf so short, the craft so long to lerne.'' - Chaucer
( ``Discere est Dolere'' -- chet )
                                       Live Strong.  No day but today.
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/

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