Re: PATH and $0

[Andreas Schwab]

bob@proulx.com (Bob Proulx) writes:

>> 2- word splitting when IFS contains non-blank characters varies
>> from one shell to the next, and in most implementations
>> (including bash and AT&T ksh, it differs from the way the shell
>> splits $PATH internally to look up a command ("/bin:" is "/bin"
>> and "" as far as PATH look up is concerned
>
> Negative.  In AT&T ksh (and others) "/bin:" is "/bin" and "." for PATH
> lookup.
>
>> while bash world splitting splits "/bin:" into only "/bin").
>
> Negative.  In bash "/bin:" is "/bin" and "." for PATH lookup.

The point is that word splitting does not preserve the empty element at
the end, thus it differs from PATH lookup.

$ (PATH=/bin:; IFS=:; for x in $PATH; do echo "$x"; done) | wc -l
1

Andreas.

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Andreas Schwab, SuSE Labs, schwab@suse.de
SuSE Linux Products GmbH, Maxfeldstraße 5, 90409 Nürnberg, Germany
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