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case statement breaks $( ) substitution
From: |
hcz |
Subject: |
case statement breaks $( ) substitution |
Date: |
Fri, 06 Oct 2006 11:55:27 +0200 |
Configuration Information [Automatically generated, do not change]:
Machine: i486
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i486'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL
-DHAVE_CONFIG_H -I. -I../bash -I../bash/include -I../bash/lib -g -O2
uname output: Linux tazzelwurm 2.6.18b #2 PREEMPT Thu Sep 28 23:52:58 CEST 2006
i686 GNU/Linux
Machine Type: i486-pc-linux-gnu
Bash Version: 3.1
Patch Level: 17
Release Status: release
Description:
case statement breaks $( ) substitution
Repeat-By:
$ echo $(
> case a in
> 1) :;;
bash: syntax error near unexpected token `;;'
The closing `)' is misinterpreted as being the end of the `$('
substitution, instead of being recognized as element of the
case block which it is part of.
Fix:
None so far. The case clause could be moved into a function
which can be called instead-
This bug has been reported several times during the last 2-3
years.
- case statement breaks $( ) substitution,
hcz <=