Re: Spaces in args, escapes, and command substitution

[Chet Ramey]

bash@zacglen.com wrote:

>> Take a look at the approach in the following example script.  `recho' is
>> part of the bash distribution; it's built while running the test suite.
>> I used `ls -1' to create a newline-delimited list of filenames.
>>
>> $ cat x3
>> [ -d scratch ] || mkdir scratch
>> cd scratch
>> touch 'a b  w' 'c d  x' 'e f  y' 'g h  z'
>>
>> IFS=$'\n'
>> recho $(ls -1 *)
>> $ ../bash-3.2/bash ./x3
>> argv[1] = <a b  w>
>> argv[2] = <c d  x>
>> argv[3] = <e f  y>
>> argv[4] = <g h  z>
>>
> 
> Easier is just:
> 
>     ls -1 *
> 
> Why not give an example which effectively does "vi `grep -l PATTERN *`"?
> Your example isn't of any use.

OK, one last try.  Replace `recho' with `vi', and `ls -1' with
`grep -l PATTERN'.  Then take a deep breath and think about what
the output of `recho' says about how the output of the command
substitution was split.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                       Live Strong.  No day but today.
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/