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Re: Spaces in args, escapes, and command substitution

From: Chet Ramey
Subject: Re: Spaces in args, escapes, and command substitution
Date: Sun, 29 Oct 2006 18:26:14 -0500
User-agent: Thunderbird (Macintosh/20060909)

address@hidden wrote:

>> Take a look at the approach in the following example script.  `recho' is
>> part of the bash distribution; it's built while running the test suite.
>> I used `ls -1' to create a newline-delimited list of filenames.
>> $ cat x3
>> [ -d scratch ] || mkdir scratch
>> cd scratch
>> touch 'a b  w' 'c d  x' 'e f  y' 'g h  z'
>> IFS=$'\n'
>> recho $(ls -1 *)
>> $ ../bash-3.2/bash ./x3
>> argv[1] = <a b  w>
>> argv[2] = <c d  x>
>> argv[3] = <e f  y>
>> argv[4] = <g h  z>
> Easier is just:
>     ls -1 *
> Why not give an example which effectively does "vi `grep -l PATTERN *`"?
> Your example isn't of any use.

OK, one last try.  Replace `recho' with `vi', and `ls -1' with
`grep -l PATTERN'.  Then take a deep breath and think about what
the output of `recho' says about how the output of the command
substitution was split.

``The lyf so short, the craft so long to lerne.'' - Chaucer
                       Live Strong.  No day but today.
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/

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