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Re: Bash arithmetic doesn't give error message on wrap.

From: Andreas Schwab
Subject: Re: Bash arithmetic doesn't give error message on wrap.
Date: Mon, 30 Apr 2007 23:23:12 +0200
User-agent: Gnus/5.110006 (No Gnus v0.6) Emacs/22.0.97 (gnu/linux)

address@hidden (Paul Jarc) writes:

> Richard Neill <address@hidden> wrote:
>> I thought testing for overflow was quite simple?
>> Isn't it just a case of looking at the carry-bit, and seeing whether it 
>> gets set?
> That's usually how it's done in assembly.  In C, it's somewhat more
> compilcated.  For example:
> result=a*b;
> if (result/a!=b) { report overflow; }

That won't work, since (signed integer) overflow is undefined in C.  A
compiler is allowed to optimize the condition to false.


Andreas Schwab, SuSE Labs, address@hidden
SuSE Linux Products GmbH, Maxfeldstraße 5, 90409 Nürnberg, Germany
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