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Re: Q: bash: trap in subshell


From: Chet Ramey
Subject: Re: Q: bash: trap in subshell
Date: Fri, 25 Apr 2008 14:56:35 -0400
User-agent: Thunderbird 2.0.0.12 (Macintosh/20080213)

Dmitry V. Levin wrote:
Hi,

I wonder whether such difference in "trap" behavior is valid:

$ sh -c 'f() { echo f; }; t() { trap f EXIT; trap; }; t'
trap -- 'f' EXIT
f
$ sh -c 'f() { echo f; }; t() { trap f EXIT; trap; }; t&'
trap -- 'f' EXIT
$ sh -c 'f() { echo f; }; t() { trap f EXIT; trap; }; (t)&'
trap -- 'f' EXIT
f

Bash does not run the exit trap in a process forked to run an
asynchronous simple command, regardless of whether or not that
command is a shell function or builtin.  It makes special provisions
to run the exit trap in a user-specified subshell -- () -- even
when that subshell is run asynchronously.

Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
                       Live Strong.  No day but today.
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/




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