Re: Bash prints syntax error when command in $(...) contains case-esac

[Jan Schampera]

Juergen Gohlke wrote:

> Description:
>        If a command in $(...) contains a case-esac construction, the 
> bash prints a syntax error instead
>        of executing the code:
>        bash: syntax error near unexpected token `;;'

In case you have trouble with code you need, use this workaround:

x=$(a=4; case $a in (3) echo a=3;; (4) echo a=4;; esac)

And yes, I've also seen this before and I thought it was fixed - maybe I 
thought of something else.

J.