Re: how to pass arguments with space inside?

[lehe]

Sorry. I won't top post again.
I tried your way but ARG_OPTS only accept the first argument and ignore the
rest.


Mike Frysinger wrote:
> 
> On Thursday 09 April 2009 17:47:59 lehe wrote:
>> Thanks Mike.
> 
> please do not top post
> 
>> Mike Frysinger wrote:
>> > On Thursday 09 April 2009 16:46:27 lehe wrote:
>> >> I was wondering how to pass arguments with space inside. For example,
>> my
>> >> bash script looks like:
>> >>
>> >> #!/bin/bash
>> >> ARG_OPTS=""
>> >> while [[ -n "$1" ]];
>> >>         ARG_OPTS="${ARG_OPTS} $1"
>> >>   shift
>> >> done
>> >>
>> >> If I pass an argument like "--options='-t 0 -v 0'", then it would be
>> >> splitted by the spaces inside, ie "--options='-t", "0", "-v" and "0".
>> >>
>> >> How can I achieve what I wish?
>> >
>> > use arrays
>> >
>> > $ f=( a "b c" d)
>> > $ printf '%s\n' "${f[@]}"
>> > a
>> > b c
>> > d
>>
>> Could you explain it a little? I don't quite get it. How to apply this to
>> argument parsing?
> 
> instead of gathering stuff into the variable ARG_OPTS, declare it as a 
> variable and gather it there:
> declare -a ARG_OPTS
> while [[ -n $1 ]] ; do
>       ARG_OPTS[${#ARG_OPTS[@]}]="$1"
>       shift
> done
> 
> then use it like i showed and the argument grouping will be preserved:
> "${ARG_OPTS[@]}"
> 
> i imagine there are plenty of bash array howtos out there if you google
> -mike
> 
> 
> 
> 

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