Re: printf "%q" and $'...'

[Antonio Macchi]

> (Note blank line in the output -- one newline from the echo command,
> and one from the actual content of $myvar.)  Using printf -v instead of
> x=$(printf) means you don't suffer from the trailing-newline-removal
> that command substitution does.
>
> I'm a bit puzzled by the original e-mail, though.  I don't see what the
> actual goal is.  If the goal is simply "put a newline character into a
> variable", then this is even simpler:
>
> myvar=$'\n'


my goal is very very stupid, like this

$ printf "%q" $(</bin/ls)

to get a "ascii form" of a binary file (something like uuencode)


but, as you can see, it does not work only for two binary chars

0x00, and 0x0a