how does escaping in "`...`" work?

[Matthew Woehlke]

(See also https://bugs.kde.org/show_bug.cgi?id=237675)

How should bash interpret escapes in constructs like "`...`"?

For example, this do what I would expect:

$ echo "`echo "you don't   say"`"
you don't   say

(That is, the contents in ``'s are parsed independent of any other 
context, except that additional `'s would need to be escaped for further 
nesting.)

But this does not:
$ echo "`echo \"you don\'t   say\"`"
you don\'t   say

I expected:
"you don't say"

That is, I expected that \" -> " substitution would not happen inside 
the ``'s outside of the context of the command substitution, since the 
quotes do not need to be escaped in that context to be seen as quotes in 
the substitution context.

Is this how it is supposed to work?

--
Matthew
Please do not quote my e-mail address unobfuscated in message bodies.
--
Will your shell have salvation? Only if it's Bourne Again.