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Re: String replacements leak small amounts of memory each time

From: Øyvind Hvidsten
Subject: Re: String replacements leak small amounts of memory each time
Date: Sun, 13 Jun 2010 23:33:25 +0200
User-agent: Cathedral Secure Mail v0.8

It could be logical leaks, or whatever is the correct english term for them. Memory that's used, and kept track of, but not used again, and not freed until the program shuts down. The memory usage is constantly increasing. I have a process using 3 gigs now, and it just runs one of those testcases (on a lot more data).

On 13/06/10 22:21, Chet Ramey wrote:
On 6/13/10 11:17 AM, address@hidden wrote:
Configuration Information [Automatically generated, do not change]:
Machine: i486
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i486' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu' 
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
-DHAVE_CONFIG_H   -I.  -I../bash -I../bash/include -I../bash/lib   -g -O2 -Wall
uname output: Linux vampiric 2.6.32-3-686-bigmem #1 SMP Thu Feb 25 06:54:30 UTC 
2010 i686 GNU/Linux
Machine Type: i486-pc-linux-gnu

Bash Version: 4.1
Patch Level: 5
Release Status: release

        When used in a script that iterates over several thousand lines of logs or 
similar data, the bash string replacement functions seem to leak memory. The Repeat-By 
list uses "ls -lR" to generate input, but any data will do (try your system 

        Start a shell, and start "top" or some other resource monitoring tool

        Try one of the following:
        while read line; do test=${line%%/*}; done<  <(ls -lR)
        while read line; do test=${line//a/b}; done<  <(ls -lR)
        while read line; do test=${line#\ }; done<  <(ls -lR)

        Also, geirha in #bash on irc.freenode.net suggested:
        var=x; for j in {1..50}; do ps -osize=,vsize= -p $$; for i in 
{1..1000}; do var=${var%%*/}; done; done;

valgrind detects no memory leaks for any of these cases.

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