Re: declare overrides errexit

[Jan Schampera]

Sascha Ziemann wrote:

>         The following code prints "a". The second false terminates the script
> but the first does not.
>         set -e
>         declare a="a"$(false)
>         echo $a
>         b="b"$(false)
>         echo $b

The first operation succeeds, the second doesn't.

The first operation is the "declare" command, and it works (and will 
seit its exit code to 0).

The second operation is a variable assignment, the status of the 
variable assignment is != 0.

"Workaround":
- first declare a
- then set a



Jan