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Re: Inconsistence when checking if a pattern is quoted or not for `==' a


From: Pierre Gaston
Subject: Re: Inconsistence when checking if a pattern is quoted or not for `==' and `=~' in [[ ]]
Date: Thu, 17 Feb 2011 16:42:02 +0200

=~ \a. matches an a followed by any char

On Thu, Feb 17, 2011 at 4:35 PM, Clark J. Wang <address@hidden> wrote:

> On Thu, Feb 17, 2011 at 9:20 PM, Andreas Schwab <address@hidden
> >wrote:
>
> > "Clark J. Wang" <address@hidden> writes:
> >
> > > See following script output:
> > >
> > > bash-4.2# cat quoted-pattern.sh
> > > [[ .a == \.a* ]] && echo 1  # not quoted
> > > [[ aa =~ \.a* ]] && echo 2  # quoted
> > >
> > > [[ aa =~ \a.  ]] && echo 3  # not quoted
> > > [[ aa =~ \a\. ]] && echo 4  # quoted
> > > bash-4.2# bash42 quoted-pattern.sh
> > > 1
> > > 3
> > > bash-4.2#
> > >
> > > From my understanding 1 2 3 4 should all be printed out.
> >
> > "aa" contains no period, so why should it be matched?
> >
> >
> If it should not be matched why I got 3 printed out?
>
>
> > Andreas.
> >
> > --
> > Andreas Schwab, address@hidden
> > GPG Key fingerprint = 58CA 54C7 6D53 942B 1756  01D3 44D5 214B 8276 4ED5
> > "And now for something completely different."
> >
>
>
>
> --
> Clark
>


 == \.a* matches a dot followed by an "a" followed by 0 or more char
=~ \.a* matches a dot followed  by 0 or more "a" anywhere in a string
 =~ \a. matches an a followed by one char, whatever that char is anywhere in
a string
aa =~ \a\.  matches an a followed by a dot  anywhere on in string


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