Re: Brace expansion inside of command substitution - broken or is it me?

[Greg Wooledge]

On Fri, Feb 18, 2011 at 10:32:13PM +0100, Peter Hofmann wrote:
> 
>  $ echo "$(echo "{1..3}")"
>  1 2 3
> 
> Huh?

Brace expansion is a funny thing.  My belief at the moment -- I'm sure
someone will correct me if I'm wrong -- is that because you've got
everything quoted up, it's all seen as one "word" by the parser.  And
it's a word that just happens to have a brace expansion in it.  So,
the parser expands it out something like this:

$ echo "$(echo "1")" "$(echo "2")" "$(echo "3")"

Counting PIDs on my sequentially-generating-PIDs OS seems to confirm that
it's running three child processes, so that lends a tiny bit of evidence
to my theory.