Re: multi line bash commands in a Makefile

[Clark J. Wang]

On Sun, Apr 10, 2011 at 7:30 PM, ali hagigat <hagigatali@gmail.com> wrote:

> Thanks Clark for the reply. 'count' is set by shell before doing make. like
> root> count=0
>
>
Have you exported the 'count' var before invoking make?


>  On Sun, Apr 10, 2011 at 3:10 PM, Clark J. Wang <dearvoid@gmail.com>
> wrote:
> > On Sun, Apr 10, 2011 at 6:17 PM, ali hagigat <hagigatali@gmail.com>
> wrote:
> >>
> >> How can i specify a multi line shell instruction as a recipe? The
> >> following returns an error:
> >>
> >> makefile27:
> >> e14:
> >>        @echo var1=$(var1)
> >>
> >> makefile25:
> >> include makefile27
> >> e12:
> >>        @echo insidee12
> >> makefile27: e13
> >>        if ( test $$count -eq 0) then echo "all: ;echo ppp" >
> >> makefile27;count=1;fi
> >
> > When you test $count it's not assigned with a value yet.
> >
> >>
> >> e13: ;
> >>
> >> make -f makefile25
> >> if ( test $count -eq 0) then echo "all: ;echo ppp" >
> makefile27;count=1;fi
> >> /bin/sh: line 0: test: -eq: unary operator expected
> >> var1=
> >>
> >> Why it complains about needing a unary operator?
> >>
> >
> > --
> > Clark J. Wang
> >
> >
>



-- 
Clark J. Wang