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Re: Ubuntu [Bug 791263] !$ works with `` but not $()


From: Chet Ramey
Subject: Re: Ubuntu [Bug 791263] !$ works with `` but not $()
Date: Wed, 01 Jun 2011 21:33:11 -0400
User-agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.17) Gecko/20110414 Lightning/1.0b2 Thunderbird/3.1.10

On 6/1/11 9:31 AM, Ralph Corderoy wrote:

> Report follows.
> 
> https://bugs.launchpad.net/ubuntu/+source/bash/+bug/791263
> 
> This is on 10.04 and also with upstream's pure bash 4.2 with no Debian
> or Ubuntu patches.
> 
>     $ echo bar >foo
>     $ >bar
>     $ ls `cat foo`
>     bar
>     $ wc !$
>     wc `cat foo`
>     0 0 0 bar
>     $ ls $(cat foo)
>     bar
>     $ wc !$
>     wc )
>     -bash: syntax error near unexpected token `)'
>     $ ls $(<foo)
>     bar
>     $ wc !$
>     wc )
>     -bash: syntax error near unexpected token `)'
>     $
> 
> I'd expect !$ to consider the last word to be $(...) just as it is happy
> with `...`.  zsh does.

Thanks for the report.  This will be fixed for the next version of bash.
In addition to $(...), process substitution and extended globbing patterns
will work as well.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/



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