[Top][All Lists]

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: converting array to string by quoting each element for eval

From: Chris F.A. Johnson
Subject: Re: converting array to string by quoting each element for eval
Date: Tue, 15 Nov 2011 17:30:40 -0500 (EST)
User-agent: Alpine 2.00 (LMD 1167 2008-08-23)

On Tue, 15 Nov 2011, Peng Yu wrote:


I find that I have to make a program quotearg.sh to convert an array
to a string by quoting each element. So that it be used for eval.

I'm not sure if there is a way that I can do eval in bash without
having to use quotearg.sh. If there is no such a way, should
quotearg.sh be added in bash (if it is not available in bash yet), as
it provides a fundamental functionality?

~/linux/bin/src/bash/quotearg/main$ cat ./main.sh
#!/usr/bin/env bash

../quotearg.sh a b c
../quotearg.sh "'" ' ' '"'
../quotearg.sh 'a' 'a b'

echo ================

args=('a' 'a b')
cmd="printf 'x%sx\n' address@hidden"
eval "$cmd"

   Why not use the array instead of making it into a single string?

$cmd "address@hidden"

   Why are you using eval or quotearg.sh? It sounds as if you are
   making the process more complicated than it need be.

   You should explain why you want it.

echo ================#the following is what I want, the above is not.

args=('a' 'a b')
arg_string=`../quotearg.sh "address@hidden"`
cmd="printf 'x%sx\n' $arg_string"
eval "$cmd"

~/linux/bin/src/bash/quotearg/main$  ./main.sh
'a' 'b' 'c'
''\''' ' ' '"'
'a' 'a b'
xa bx

   Chris F.A. Johnson, <http://cfajohnson.com/>
   Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)

reply via email to

[Prev in Thread] Current Thread [Next in Thread]