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Re: [bug] Bash translates >&$var into &>$var for exported functions.


From: Chet Ramey
Subject: Re: [bug] Bash translates >&$var into &>$var for exported functions.
Date: Wed, 25 Jan 2012 16:02:12 -0500
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.7; rv:8.0) Gecko/20111105 Thunderbird/8.0

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On 1/23/12 2:50 AM, Dan Douglas wrote:
> Hello, In the case of exported functions, Bash interprets a copy descriptor 
> followed by an expansion as the >& synonym for &>, resulting in the output 
> going to a file named as the value of the FD it's given.  This only applies 
> to 
> ">&$var" and not "<&$var". I've tested various quoting, Is there some way 
> around this?

Nope, it's a bug.  The command printing code is a little aggressive about
translating >& to &>.  I've attached a patch that should be enough to
get you by.

Chet
- -- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/
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Attachment: print-redirects.patch
Description: Source code patch


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