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Re: Inconsistent quote and escape handling in substitution part of param


From: John Kearney
Subject: Re: Inconsistent quote and escape handling in substitution part of parameter expansions.
Date: Tue, 28 Feb 2012 23:49:24 +0100
User-agent: Mozilla/5.0 (X11; Linux i686; rv:10.0) Gecko/20120129 Thunderbird/10.0

On 02/28/2012 11:44 PM, Chet Ramey wrote:
> echo "$(echo '$bar')"

actually these both output the same in bash
echo "$(echo '$bar')"
echo $(echo '$bar')



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