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Re: status on $[arith] for eval arith vsl $((arith))??

From: Linda Walsh
Subject: Re: status on $[arith] for eval arith vsl $((arith))??
Date: Sat, 07 Apr 2012 14:50:17 -0700
User-agent: Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv: Gecko/20100228 Lightning/0.9 Thunderbird/ Mnenhy/

Mike Frysinger wrote:

On Saturday 07 April 2012 16:45:55 Linda Walsh wrote:
Is it an accidental omission from the bash manpage?

it's in the man page.  read the "Arithmetic Expansion" section.

My 4.2 manpage says:

   Arithmetic Expansion
       Arithmetic  expansion allows the evaluation of an arithmetic expression
       and the substitution of the result.  The format for  arithmetic  expan-
       sion is:


       The  expression  is  treated  as if it were within double quotes, but a
       double quote inside the parentheses  is  not  treated  specially.   All
       tokens in the expression undergo parameter expansion, string expansion,
       command substitution, and quote removal.  Arithmetic expansions may  be

       The  evaluation  is performed according to the rules listed below under
       ARITHMETIC EVALUATION.  If expression is invalid, bash prints a message
       indicating failure and no substitution occurs.

No mention of square brackets.

What's yours say?

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