Re: Compare 2 arrays.

[Quinn Fissler]

See any problem here?

########
#!/bin/bash
# [PL] Porownuje dwie tablice, zwraca prawde/falsz.
set -x
A=( "$1" )
B=( "$2" )
EQUAL=0

if [ ${#A[@]} -eq ${#B[@]} ]; then
for id in `seq 0 2 $[ ${#A[@]} - 2 ]`; do
if [ "${A[ $id ]}" == "${B[ $id ]}" ]; then
EQUAL=1
else
EQUAL=0
break
fi
done
fi
echo $EQUAL

########
dog@zen:/home/dog$ ./pl.bash "ls" "ls"
+ A=("$1")
+ B=("$2")
+ EQUAL=0
+ '[' 1 -eq 1 ']'
++ seq 0 2 -1
+ echo 0
0
dog@zen:/home/dog$

########

On 29 May 2012 17:43, Akasei Yoshiko <akasei@inoto.net> wrote:
> I have something like that:
>
>> #!/bin/bash
>> # [PL] Porownuje dwie tablice, zwraca prawde/falsz.
>>
>> A=( "$1" )
>> B=( "$2" )
>> EQUAL=0
>>
>> if [ ${#A[@]} -eq ${#B[@]} ]; then
>>       for id in `seq 0 2 $[ ${#A[@]} - 2 ]`; do
>>               if [ "${A[ $id ]}" == "${B[ $id ]}" ]; then
>>                       EQUAL=1
>>               else
>>                       EQUAL=0
>>                       break
>>               fi
>>       done
>> fi
>>
>> echo $EQUAL
>
>
> When i type:
>> user[~] $ ./compare "wget 0" "wget 0"
>> 0
>
> Returns zero.
>
> How do this properly?
>