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Re: different exit codes in $? and address@hidden

From: Wladimir Sidorenko
Subject: Re: different exit codes in $? and address@hidden
Date: Sun, 14 Oct 2012 12:19:58 +0300

Provided '-o pipefail' is not specified.

2012/10/14 Andreas Schwab <address@hidden>:
> Wladimir Sidorenko <address@hidden> writes:
>> To my mind the '!' operator should have had a higher precedence during
>> parsing command line arguments than the pipe and applied only to the
>> command it was immediately preceding. So that in
>> ! command1 | command2 | command3
>> it would only negate command1.
> Which doesn't make sense, since the exit code of command1 has no
> significance.  The exit code of a pipeline is that of the last command.
> Andreas.
> --
> Andreas Schwab, address@hidden
> GPG Key fingerprint = 58CA 54C7 6D53 942B 1756  01D3 44D5 214B 8276 4ED5
> "And now for something completely different."

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