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Re: Regular expression matching fails with string RE


From: John Kearney
Subject: Re: Regular expression matching fails with string RE
Date: Wed, 17 Oct 2012 04:17:56 +0200
User-agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:16.0) Gecko/20121010 Thunderbird/16.0.1

Am 17.10.2012 03:13, schrieb Clark WANG:
> On Wed, Oct 17, 2012 at 5:18 AM, <address@hidden> wrote:
>
>> Bash Version: 4.2
>> Patch Level: 37
>>
>> Description:
>>
>> bash -c 're=".*([0-9])"; if [[ "foo1" =~ ".*([0-9])" ]]; then echo
>> ${BASH_REMATCH[0]}; elif [[ "bar2" =~ $re ]]; then echo ${BASH_REMATCH[0]};
>> fi'
>>
>> This should output foo1. It instead outputs bar2, as the first match fails.
>>
>>
>> From bash's man page:
>        [[ expression ]]
>               ... ...
>               An additional binary operator, =~, is available, with  the
> same
>               ... ...
>               alphabetic characters.  Any part of the pattern may be quoted
> to
>               force  it  to  be  matched  as  a string.  Substrings matched
> by
>               ... ...
Drop the quotes on the regex

bash -c 're=".*([0-9])"; if [[ "foo1" =~ .*([0-9]) ]]; then echo
${BASH_REMATCH[0]}; elif [[ "bar2" =~ $re ]]; then echo ${BASH_REMATCH[0]};
fi'

outputs foo1









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