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problem with extended regular expression in bash 4.1


From: Alex Chupin (achupin)
Subject: problem with extended regular expression in bash 4.1
Date: Sat, 24 Nov 2012 21:08:16 +0000

Dear All,

Can someone shed light on the difference in behaviour of bash 4.1. and 3.25? I 
am out of ideas. 

Regards,
Alexander Chupin

$ bash --version; s=12345;if [[ "$s" =~ '^[0-9]+$' ]]; then echo it is a 
number; else echo it is NOT a number; fi
GNU bash, version 4.1.2(1)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2009 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
it is NOT a number


$ bash --version; s=12345;if [[ "$s" =~ '^[0-9]+$' ]]; then echo it is a 
number; else echo it is NOT a number; fi
GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2005 Free Software Foundation, Inc.
it is a number





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