Re: Local variables overriding global constants

[Nikolai Kondrashov]

On 04/03/2013 10:43 AM, Chris F.A. Johnson wrote:
> On Wed, 3 Apr 2013, Nikolai Kondrashov wrote:
> > I.e. this:
> >
> > bash -c 'declare -r v; a() { declare -r v; }; a'
> >
> > Results in:
> >
> > bash: line 0: declare: v: readonly variable
>
> It doesn't work because you are trying to redefine an existing
> readonly variable.

Yes, but I'm explicitly redefining it locally, only for this function.
And this works for variables previously defined in the calling function.

> > While this works:
> >
> > bash -c 'a() { declare -r v; }; b() { declare -r v; a; }; b'
>
> It works because both instances are local to a function and don't
> exist outside their own functions.

Not true.

This:

    bash -c 'a() { echo "$v"; }; b() { declare -r v=123; a; }; b'

Produces this:

    123

Sincerely,
Nick