Re: Local variables overriding global constants

[Nikolai Kondrashov]

> > It works because both instances are local to a function and don't
> > exist outside their own functions.
>
> Not true.
>
> This:
>
> bash -c 'a() { echo "$v"; }; b() { declare -r v=123; a; }; b'
>
> Produces this:
>
> 123

Moreover, this:

    bash -c 'a() { v=2; }; b () { v=1; a; echo "$v"; }; b'

Produces this:

    2