Re: `declare -fp` mishandles heredoc with || statement

[Mike Frysinger]

On Saturday 01 June 2013 17:07:33 Chet Ramey wrote:
> On 5/31/13 10:37 PM, Mike Frysinger wrote:
> > simple code snippet:
> > $ cat test.sh
> > func() {
> > cat > / <<EOF || echo FAIL
> > 11
> > EOF
> > }
> > declare -fp
> > 
> > when run, we see the || statement is incorrectly moved to after the
> > heredoc: $ bash ./test.sh
> > func ()
> > {
> >     cat > /  <<EOF
> > 11
> > EOF
> >  || echo FAIL
> > }
> > 
> > every version of bash i tried fails this way (2.05b through 4.2.45)
> 
> I don't get this.  I see, when using bash-4.2.45:
> 
> $ ./bash-4.2-patched/bash ./x1
> func ()
> {
>     cat > /tmp/xxx  <<EOF ||
> 11
> EOF
>  echo FAIL
> }
> 
> I get the same thing going all the way back to bash-4.0.  I see the same
> results you do on bash-3.2.51, but that's old enough that it's not going
> to change.

err, yeah, sorry.  running too many versions of bash (like 10) made me miss 
the subtle nuance of the || being up top vs down below.  bash-4.0+ work.
-mike

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