Re: `printf -v foo ""` does not set foo=

[Mike Frysinger]

On Monday 24 June 2013 16:13:01 Chet Ramey wrote:
> On 6/17/13 1:27 AM, Mike Frysinger wrote:
> > simple test code:
> >     unset foo
> >     printf -v foo ""
> >     echo ${foo+set}
> > 
> > that does not display "set".  seems to have been this way since the
> > feature was added in bash-3.1.
> 
> printf returns immediately if the format string is null.  It has always
> been implemented this way.

seems like when the -v arg is in use, that [otherwise reasonable] shortcut 
should be not taken ?
-mike

signature.asc
Description: This is a digitally signed message part.