Re: read builtin. input processes improperly inheriting IFS setting

[Greg Wooledge]

On Fri, Jul 26, 2013 at 10:38:46PM +0200, Andreas Schwab wrote:
> Greg Wooledge <wooledg@eeg.ccf.org> writes:
> 
> > Your unquoted $instring is being split into fields by bash, which is
> > operating with IFS=: at that point.
> 
> Variable assignments are supposed to be performed _after_ redirections
> (read is not a special built-in).

Do you mean variable expansions?  I'm willing to concede that there may
be a bug here, but your explanation is confusing to me.

Here's the code in question, simplified even further:

imadev:~$ unset IFS
imadev:~$ foo=a/b/c
imadev:~$ cat < <(echo $foo)
a/b/c
imadev:~$ IFS=/ cat < <(echo $foo)
a b c

Clearly the IFS assignment is affecting the expansion of $foo inside
the process substitution.  This has nothing to do with read.

By the way, I get the same result in both 4.3.0-alpha and 1.14.7 (except
that I can't unset IFS in 1.14.7).