Re: Bug in function return statement in while subshell

[Chet Ramey]

On 7/29/13 1:15 PM, Roman Rakus wrote:
> On 07/29/2013 05:06 PM, Chet Ramey wrote:
>> On 7/29/13 10:55 AM, Roman Rakus wrote:
>>> I didn't take a look on where the problem could be, but it is discussed on
>>> stackoverflow [1].
>>>
>>> Looks like return builtin falsely exit execution of while loop instead of
>>> function.
>>
>> What would you like to see happen?  You're in a subshell: the function
>> can't return, since this is not the shell that called it.  Do you want
>> parent and child shells both continuing execution after the function call?
>>
>> Chet
>>
> As Chris said, some error, because return is not in function.
> 
> Example:
> f1() {
>     : | while :; do return 3; done
>     echo $?
>     return 1
> }
> echo $?
> f1; echo $?
> return 2
> 
> Looks like the bash doesn't restore the i'm-in-function indicator when
> running compound command (like while or if) in functions' subshell.

I'm not sure exactly what you mean by this, since the `return' call in
the pipeline inside the function completes without an error.  Bash
prints an error message due to the `return 2' not occurring while in
a function.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/