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Bash gives error string splice

From: Williams, Zak
Subject: Bash gives error string splice
Date: Thu, 8 Aug 2013 16:18:55 +0000

Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: Linux-gnu
Compiler: gcc
Compilation CFLAGS: Compilation CFLAGS:  -DPROGRAM='bash' 
-DCONF_HOSTTYPE='x86_64' -DCONF_OSTYPE='linux-gnu' 
-DCONF_MACHTYPE='x86_64-pc-linux-gnu' -DCONF_VENDOR='pc' 
-DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H   -I.  
-I../bash $/bash -I../bash/include -I../bash/lib   -g -O2 -Wall
uname output: Linux wiggum-v5 2.6.32-5-amd64 #1 SMP Fri May 10 08:43:19 UTC 
2013 x86_64 GNU/Linux
Machine Type: x86_64-pc-linux-gnu

Bash Version: 4.1
Patch Level: 5
Release Status: release

               The bash script compiles and runs just fine when running it via 
command line (./script_name). However what I want to do is only run the script 
if it has not been run that day. I also want to run this whenever a terminal is 
opened up so I call the script within .bashrc. When ran from .bashrc I get the 
error (path of script): 7 : Bad substitution. The script runs fine without 
calling from .bashrc (it is the last line in the .bashrc file).

               Replicating the code I have below. You will then want to call 
this script via the bottom of the .bashrc file ( sh [path to script here] ).

current_date=$(date +%Y-%m-%d)
modded_date=$(stat -c %z /home/dev/login_startup)
#Line that generates the error
echo $trial
echo $current_date

#More stuff down here

If you have any questions feel free to email me. I hope I explained everything 
clearly, thanks for taking the time to read this!

Zak Williams
HP Tools Team Intern


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