"jobs" builtin: print zero exit status

[Dmitry Bolshakov]

   Hi!
   imho "jobs" should either print zero exit status or it should be
   documented that "Done" means zero exit status
   $ bash -c 'set -m; perl -e "sleep 1; exit 123"& { sleep 3; jobs -l; }'
   [1]+е║ Exit 123е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║ perl -e "sleep 1; exit 123"
   ok, I see exit status
   but
   $ bash -c 'set -m; perl -e "sleep 1; exit 0"& { sleep 3; jobs -l; }'
   [1]+е║ Doneе║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║ perl -e "sleep 1; exit 0"
   imho "Exit 0" would be better for scripting

   --

   with best regards
   Dmitry Bolshakov