Re: Strange problem with source

[Bert Barbe]

I think what happens is the following:

"Using declare limits the scope of the variable."
Since the source of b happens inside the function includeFile, the 
declare of testVariable happens inside that function, and it's scope is 
limited to that function.

Kind regards,
Bert

On 01/12/2014 01:31 PM, Cecil Westerhof wrote:
> Is this a known problem?
>
> I have a strange problem with source. Sometimes variables are not
> defined, but functions are.
>
> I have a file a with:
>      function includeFile() {
>          local fileName
>          local needsToExist=true
>
>          if [[ ${1} == "--notNeeded" ]] ; then
>              needsToExist=false; shift
>          fi
>          if [[ ${#} -ne 1 ]] ; then
>              echo "includeFile [--notNeeded] <INPUT_FILE>"
>              return 1
>          fi
>          INPUTFILE=${1}; shift
>
>          if  [ -s ${INPUTFILE} -a -f ${INPUTFILE} -a -r ${INPUTFILE} ] ; then
>              source ${INPUTFILE}
>          else
>              if [[ ${needsToExist} != false ]] ; then
>                  echo "${INPUTFILE} could not be used"
>                  return 1
>              fi
>          fi
>      }
>
>      includeFile b
>
> In file b I have:
>      declare testVariable="testing"
>      echo ${testVariable}
>
>      function testFunction {
>          :
>      }
>
> When doing:
>      source a
>
> The string "testing" is printed and the function testFunction is
> defined, but the variable testVariable is not defined.
>
> When I change in file a the includeFile to source, testVariable is
> defined.
>
> Very strange indeed. Especially there includeFile does a source.
>
> I am using bash 4.2.42(1)-release.