Re: BASH_ARGV -- arguments are reversed

[Clark Wang]

On Fri, Nov 28, 2014 at 1:07 PM, William Park <opengeometry@yahoo.ca> wrote:

Hi all,

I just noticed that BASH_ARGV contains commandline arguments in reverse.

That's because it's a stack. According the bash manual: "The final parameter of the last subroutine call is at the top of the stack; the first parameter of the initial call is at the bottom."

    $ cat > x.sh
    #!/bin/sh
    declare -p BASH_ARGV
    ^D

    $ sh x.sh 1 2 3 4 5
    declare -a BASH_ARGV='([0]="5" [1]="4" [2]="3" [3]="2" [4]="1")'
--
William