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Re: Bash "bug" - in "read -e -r var"
From: |
Chet Ramey |
Subject: |
Re: Bash "bug" - in "read -e -r var" |
Date: |
Mon, 15 Dec 2014 21:40:41 -0500 |
User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.10; rv:31.0) Gecko/20100101 Thunderbird/31.2.0 |
On 12/15/14 11:13 AM, Dan Douglas wrote:
> Ah ok I thought -e basically negated the effect of -r for some reason but I
> guess not (like you can still use \ to escape line continuations without -r it
> seems).
They're separate but kind of clumsy to use together for line continuations.
`read' ends up calling readline N times for every N-1 backslash-escaped
newlines. If -r is supplied it doesn't need to do anything out of the
ordinary for \<newline>.
In terms of backslash escaping characters in the line read, backslash
isn't really special to readline, it's just mapped to self-insert. You
still have to use quoted-insert to insert characters that are bound to
line editing commands.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/