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Re: declare a="$b" if $a previously set as array

From: Dan Douglas
Subject: Re: declare a="$b" if $a previously set as array
Date: Mon, 15 Dec 2014 23:56:32 -0600
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On Sunday, December 14, 2014 09:44:16 PM Stephane Chazelas wrote:
> but:
> x='($(uname>&2))' bash -c 'f() { a[0]=x; declare a=$x; }; f'
> is not, because when in a function, declare ignores variables by
> the same name that have not been declared in that same scope
> (even if they have been *set* in that context)
> So it's more unlikely to be a problem than I thought it would be
> as "declare" is mostly used in functions. 

Indeed I was just about to point this out. It's a rare scenario at least in my 
code to either declare something twice in the same scope or rely upon a global 
being in a particular state.

Dan Douglas

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