Re: bash --debugger on a script with no arguments

[Chet Ramey]

On 4/29/15 1:51 PM, Rocky Bernstein wrote:
> Now I am really confused and I am not sure we are talking about the same
> thing

We really are.

> In bash-4.3.30 on ftp://ftp.gnu.org/gnu/bash at line 723 of shell.c
> there is: 
> 
>   if (debugging_mode && locally_skip_execution == 0 && running_setuid == 0
> && dollar_vars[1])
>     start_debugger ();
> 
> Shouldn't dollar_vars[1] be dollar_vars[0] (the name of the script to be
> debugged)?

I understand your question, and, as I said, that code was changed back last
November when I was looking at

http://lists.gnu.org/archive/html/bug-bash/2014-11/msg00137.html

As part of investigating it, I noticed the same thing you just reported,
so I fixed that as well.  The change log entries for both issues appear
one right after the other.  That code is in the bash devel branch on
savannah.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/