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Re: bash --debugger on a script with no arguments


From: Chet Ramey
Subject: Re: bash --debugger on a script with no arguments
Date: Wed, 29 Apr 2015 19:21:10 -0400
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.10; rv:31.0) Gecko/20100101 Thunderbird/31.6.0

On 4/29/15 1:51 PM, Rocky Bernstein wrote:
> Now I am really confused and I am not sure we are talking about the same
> thing

We really are.

> In bash-4.3.30 on ftp://ftp.gnu.org/gnu/bash at line 723 of shell.c
> there is: 
> 
>   if (debugging_mode && locally_skip_execution == 0 && running_setuid == 0
> && dollar_vars[1])
>     start_debugger ();
> 
> Shouldn't dollar_vars[1] be dollar_vars[0] (the name of the script to be
> debugged)?

I understand your question, and, as I said, that code was changed back last
November when I was looking at

http://lists.gnu.org/archive/html/bug-bash/2014-11/msg00137.html

As part of investigating it, I noticed the same thing you just reported,
so I fixed that as well.  The change log entries for both issues appear
one right after the other.  That code is in the bash devel branch on
savannah.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/



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