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Re: BUG?: (or what's going on?) test for NL == NL fails (bash-4.3.39(3)-


From: Linda Walsh
Subject: Re: BUG?: (or what's going on?) test for NL == NL fails (bash-4.3.39(3)-release)
Date: Sun, 02 Aug 2015 15:11:17 -0700
User-agent: Thunderbird



Charles Daffern wrote:
On 02/08/15 20:30, Linda Walsh wrote:
 if [[ $(printf "\n") == $'\n' ]]; then echo T; else echo F; fi
F

The command substitution operators ($(...) and `...`) strip all trailing
linefeeds. You are left with an empty string here.

The usual workarounds I see (where necessary) are hacks like this:

variable=$(command; echo x); variable=${variable%?x}
----
        I see what you mean --- erk...
I think the process substitution doesn't, since you need
to explicitly use a -t switch if you want to strip the "\n"'s off

Thanks!





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