|Subject:||-e does not take effects in subshell|
|Date:||Tue, 11 Aug 2015 11:42:29 +0000|
I have a export function looking like:
echo "build okay"
I wish to use this function this way:
mybuild && do_other_stuff
But whatever (success or failure) make returns "build okay" is always printed and do_other_stuff always gets executed, which is my expectation.
I have found below descriptions on bash manual.
-e Exit immediately if a pipeline (which may consist of a single simple command), a subshell command enclosed in parentheses, or one of the
commands executed as part of a command list enclosed by braces (see SHELL GRAMMAR above) exits with a non-zero status. The shell does not
exit if the command that fails is part of the command list immediately following a while or until keyword, part of the test following the if
or elif reserved words, part of any command executed in a && or || list except the command following the final && or ||, any command in a
pipeline but the last, or if the command's return value is being inverted with !. A trap on ERR, if set, is executed before the shell
exits. This option applies to the shell environment and each subshell environment separately (see COMMAND EXECUTION ENVIRONMENT above), and
may cause subshells to exit before executing all the commands in the subshell.
To my understanding, the purpose of these limitations is to prevent the shell exiting if a command fails in conditional testing context such as if, elif, while, isn't it?
My confusion is why the && operator disables `-e' effects in the subshell. It does not make sense to continue executing remaining commands since I wish the subshell to stop on error.
Or I am wrong and the results match the original designs?
|[Prev in Thread]||Current Thread||[Next in Thread]|