doesn't bash do variable subst. or quote removal on function statement

[Linda Walsh]

Reuti wrote:
> Am 08.01.2016 um 21:36 schrieb Piotr Grzybowski:
>
>   
> > hello Linda,
> >
> > On Fri, Jan 8, 2016 at 9:14 PM, Linda Walsh <bash@tlinx.org> wrote:
> >     
> > > For what it's worth, It might be useful to have something like
> > > 'command' [..]
> > >       
> > that would be useful, a keyword like:
> >
> > function p params;
> >     
But 'function p'... is already a lead-in to a function definition, i.e:
function xyz { :; }  #(create function foo)
> AFAICS putting the name in quotes (single or double) will prefer the function 
> over the alias, but it will fall back to a command if there is no function.
>
> 'P' params
>   
----
   Not in a function definition (i.e. this is broken AFAIAC in bash).
I.e.
>  'func' () { :; }
-bash: `'func'': not a valid identifier
>  function 'func' () { : ; }
-bash: `'func'': not a valid identifier
>  function "func" () { :; }
-bash: `"func"': not a valid identifier
---
That's weird.  while, _maybe_ I could see the 1st one not working
if looking for a bash keyword, but the 2nd & third forms seems odd.
I thought variable substitution and quote-removal was supposed
to happen before the statement is executed ??

I.e.: this _seems_ broken:

>  shopt -s expand_aliases; alias my=declare
>  declare fn=myfunc                    ## function name in variable 
doesn't work
>  function $fn { echo $fn ; }
-bash: `$fn': not a valid identifier
> my -pf myfunc
-bash: declare: myfunc: not found
>  def="function $fn () { echo $fn ; }"  ## but same statement, eval'd works
>  eval $def                           
>  my -f myfunc
myfunc ()
{
   echo myfunc
}

I.e. while having the function name in a variable doesn't work
interactively, it does work when used with eval.